MATHEMATICS FORM 1 – APPROXIMATIONS

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   Is the process of rounding off a number in the given places in rounding makes numbers easier to deal with but at the same time reduces their accuracy.

The methods used for approximation or rounding off numbers are decimal places and significant figures.

ROUNDING OFF PROCEDURES

i) If the first neglected digit is greater or equal to 5 the digit occupying the place value will increase by 1 unit

ii) If the first neglected number is less than five, then the number occupying the required place value will remain unchanged.

ROUNDING OFF NUMBERS

 Examples

1. Round off the following numbers to the nearest whole number.

 
 

a)    3425

b)   7.283

c)    6.674

d)    0.625

e)    36.12

f)      5446

 
 

Solutions

 
 

a)    3425≈ 3000

b)   7.283≈7

c)    6.674≈7

d)    0.625≈1

e)    36.12≈36

f)      5446≈5000

 
 

2. Round off the following to

a)    1 decimal place.

b)   2 decimal places.

c)    3 decimal places.

a)    23.7016

b)   0.0094

 
 

Solution

 
 

  1. 23.7016≈23.7 to 1 decimal place.
  2. 23.7016≈23.70 to 2 decimal place.
  3. 23.7016≈23.702 to 3 decimal places.

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b) 0.0094

 
 

a)    0.0094≈0.0 to 1 decimal place.

b)   0.0094≈0.001 to 2 decimal place.

c)    0.0094≈0.009 to 3 decimal places.

 
 

3. Round off the following number to the nearest

a)    Whole number

b)   Tenth

c)    Hundredth

 
 

       i.    0.625

     ii.     8.385

 
 

 
 

 
 

Solution

       i.            0.625

 
 

a)    0.625≈1 to whole numbers

b)   0.625≈0.6 to tenth

c)    0.625≈0.63 to hundredths

 
 

ii. 8.385

 
 

a)    8.385≈8 to whole numbers

b)   8.385≈8.4 to tenth

 
 

c)    8.385≈ 8.39 to hundredths

 
 

Example: Round off 84678 to

i) Tens

            Solution

            84678 = 84700

            ii) Hundreds

            Solution

            84678 = 85000

            iii) Thousands

            Solution

            84678 = 80000

      Example: Round off 179999 correct to i) hundreds   ii) Thousand   iii) Tens iv )Ten thousands

            Solution

            i) 179999edu.uptymez.com  180000

            ii) 180000

            iii) 180000

            iv) 180000

Significant Figures
The are the total number of digits in the given number including zero’s which are in between non-zero digits.
Note

 i) Zero is a significant figure when is in between two non – zero digits 

 ii) When zero is an outcome of approximation (rounding off) where a    9 receives l and becomes ten, then zero of ten is a significant figure.

Examples: determine the number of significant figures in the following

i) 20896100

            = There are six significant figures

ii) 0.00025060

            = There are four significant figures

iii) 2.00008453

            = There are nine significant figures

Examples: Re write following numbers correcting to the required of significant figures.

a.   0.23678 to 3 significant figures

            Solution

            0.23678

            = 0.24

b.    2.09478 to 3 significant figures

            Solution

            2.09478

            = 2.09

c.   0.009994 to 2 significant figures

            Solution

            0.009994

            = 0.010

d.  0.00931225697 to 7significant figures

            Solutions

            0.00931225697

            = 0.0093123

Exercise

Re write the following numbers correctly to

a.  10.999009 to three significant figures

            Solution

            10.999009

            = 11.0

b.   705.4005 to six significant figures

            Solution

            705.4005

            = 705.401

C.   847910 to three significant figures

            Solution

            847910

            = 848000

Approximations in operations

When you want to check approximation whether a calculation is correct or not. Round each number in the calculation to 1 significant figure. Do the calculation mentally.
Example:
A group of 42 people go to the cinema, which cost 680/- each. What is the approximation total cost?
Solution
Round 42 to 40 and 680 to 700
Therefore 40 x 700 = 28,000/=
Note: The exact cost is 28,560 The approximation is 28,000 which is close.

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